Hybrid-pi is a popular circuit model used for analyzing the small signal behavior of bipolar junction and field effect transistors. Sometimes it is also called Giacoletto model because it was introduced by L.J. Giacoletto in 1969.[1] The model can be quite accurate for low-frequency circuits and can easily be adapted for higher frequency circuits with the addition of appropriate inter-electrode capacitances and other parasitic elements.
The hybrid-pi model is a linearized two-port network approximation to the BJT using the small-signal base-emitter voltage,
stylevbe
stylevce
styleib
styleic
A basic, low-frequency hybrid-pi model for the bipolar transistor is shown in figure 1. The various parameters are as follows.
gm=\left.
ic | |
vbe |
\right\vert | |
vce=0 |
=
IC | |
VT |
styleIC
styleVT=
kT | |
e |
stylek
stylee
styleT
styleVT
r\pi=\left.
vbe | |
ib |
\right\vert | |
vce=0 |
=
VT | |
IB |
=
\beta0 | |
gm |
styleIB
style\beta0=
IC | |
IB |
stylero=\left.
vce | |
ic |
\right\vert | |
vbe=0 |
~=~
1 | |
IC |
\left(VA+VCE\right)~ ≈ ~
VA | |
IC |
styleVA
The output conductance, g, is the reciprocal of the output resistance, r:
gce=
1 | |
ro |
The transresistance, r, is the reciprocal of the transconductance:
rm=
1 | |
gm |
The full model introduces the virtual terminal, B′, so that the base spreading resistance, rbb, (the bulk resistance between the base contact and the active region of the base under the emitter) and rb′e (representing the base current required to make up for recombination of minority carriers in the base region) can be represented separately. Ce is the diffusion capacitance representing minority carrier storage in the base. The feedback components, rb′c and Cc, are introduced to represent the Early effect and Miller effect, respectively.[4]
A basic, low-frequency hybrid-pi model for the MOSFET is shown in figure 2. The various parameters are as follows.
gm=\left.
id | |
vgs |
\right\vert | |
vds=0 |
\scriptstyleID
gm=
2ID | |
VGS-Vth |
\scriptstyleID
\scriptstyleVth
\scriptstyleVGS
The combination:
Vov=VGS-Vth
ro=\left.
vds | |
id |
\right\vert | |
vgs=0 |
\begin{align} ro&=
1 | \left( | |
ID |
1 | |
λ |
+VDS\right)\\ &=
1 | |
ID |
\left(VEL+VDS\right) ≈
VEL | |
ID |
\end{align}
λ=
1 | |
VEL |
The drain conductance is the reciprocal of the output resistance:
gds=
1 | |
ro |