In mathematics, the characteristic equation (or auxiliary equation) is an algebraic equation of degree upon which depends the solution of a given th-order differential equation[1] or difference equation.[2] [3] The characteristic equation can only be formed when the differential or difference equation is linear and homogeneous, and has constant coefficients.[4] Such a differential equation, with as the dependent variable, superscript denoting nth-derivative, and as constants,
any(n)+an-1y(n-1)+ … +a1y'+a0y=0,
anrn+an-1rn-1+ … +a1r+a0=0
yt+n=b1yt+n-1+ … +bnyt
has characteristic equation
rn-
n-1 | |
b | |
1r |
- … -bn=0,
discussed in more detail at Linear recurrence with constant coefficients.
The characteristic roots (roots of the characteristic equation) also provide qualitative information about the behavior of the variable whose evolution is described by the dynamic equation. For a differential equation parameterized on time, the variable's evolution is stable if and only if the real part of each root is negative. For difference equations, there is stability if and only if the modulus of each root is less than 1. For both types of equation, persistent fluctuations occur if there is at least one pair of complex roots.
The method of integrating linear ordinary differential equations with constant coefficients was discovered by Leonhard Euler, who found that the solutions depended on an algebraic 'characteristic' equation. The qualities of the Euler's characteristic equation were later considered in greater detail by French mathematicians Augustin-Louis Cauchy and Gaspard Monge.
Starting with a linear homogeneous differential equation with constant coefficients,
any(n)+an-1y(n-1)+ … +a1y\prime+a0y=0,
anrnerx+an-1rn-1erx+ … +a1rerx+a0erx=0
anrn+an-1rn-1+ … +a1r+a0=0.
y(x)=c1e3+c2e11+c3e40
c1
c2
c3
Solving the characteristic equation for its roots,, allows one to find the general solution of the differential equation. The roots may be real or complex, as well as distinct or repeated. If a characteristic equation has parts with distinct real roots, repeated roots, or complex roots corresponding to general solutions of,, and, respectively, then the general solution to the differential equation is
y(x)=yD(x)+
y | |
R1 |
(x)+ … +
y | |
Rh |
(x)+
y | |
C1 |
(x)+ … +
y | |
Ck |
(x)
The linear homogeneous differential equation with constant coefficients
y(5)+y(4)-4y(3)-16y''-20y'-12y=0
r5+r4-4r3-16r2-20r-12=0
(r-3)(r2+2r+2)2=0
y(x)=c1e3x+
x(c | |
e | |
2 |
\cosx+c3\sinx)+
x(c | |
xe | |
4 |
\cosx+c5\sinx)
The superposition principle for linear homogeneous says that if are linearly independent solutions to a particular differential equation, then is also a solution for all values .[7] Therefore, if the characteristic equation has distinct real roots, then a general solution will be of the form
yD(x)=c1
r1x | |
e |
+c2
r2x | |
e |
+ … +cn
rnx | |
e |
If the characteristic equation has a root that is repeated times, then it is clear that is at least one solution. However, this solution lacks linearly independent solutions from the other roots. Since has multiplicity, the differential equation can be factored into
\left(
d | |
dx |
-r1\right)ky=0.
\left(
d | |
dx |
-r1\right)
r1x | |
ue |
=
d | |
dx |
r1x | |
\left(ue |
\right)-r1
r1x | |
ue |
=
d | |
dx |
r1x | |
(u)e |
+r1
r1x | |
ue |
-r1
r1x | |
ue |
=
d | |
dx |
r1x | |
(u)e |
\left(
d | |
dx |
-r1\right)k
r1x | |
ue |
=
dk | |
dxk |
r1x | |
(u)e |
=0.
dk | |
dxk |
(u)=u(k)=0.
yR(x)=
r1x | |
e |
\left(c1+c2x+ … +ckxk-1\right).
If a second-order differential equation has a characteristic equation with complex conjugate roots of the form and, then the general solution is accordingly . By Euler's formula, which states that, this solution can be rewritten as follows:
\begin{align} y(x)&=c1e(a+c2e(a\ &=c1eax(\cosbx+i\sinbx)+c2eax(\cosbx-i\sinbx)\\ &=\left(c1+c2\right)eax\cosbx+i(c1-c2)eax\sinbx\end{align}
For example, if, then the particular solution is formed. Similarly, if and, then the independent solution formed is . Thus by the superposition principle for linear homogeneous differential equations, a second-order differential equation having complex roots will result in the following general solution:
yC(x)=eax(C1\cosbx+C2\sinbx)
This analysis also applies to the parts of the solutions of a higher-order differential equation whose characteristic equation involves non-real complex conjugate roots.