In mathematical economics, Topkis's theorem is a result that is useful for establishing comparative statics. The theorem allows researchers to understand how the optimal value for a choice variable changes when a feature of the environment changes. The result states that if f is supermodular in (x,θ), and D is a lattice, then
*(\theta)=\argmax | |
x | |
x\inD |
f(x,\theta)
This example will show how using Topkis's theorem gives the same result as using more standard tools. The advantage of using Topkis's theorem is that it can be applied to a wider class of problems than can be studied with standard economics tools.
A driver is driving down a highway and must choose a speed, s. Going faster is desirable, but is more likely to result in a crash. There is some prevalence of potholes, p. The presence of potholes increases the probability of crashing. Note that s is a choice variable and p is a parameter of the environment that is fixed from the perspective of the driver. The driver seeks to
maxsU(s,p)
We would like to understand how the driver's speed (a choice variable) changes with the amount of potholes:
\partials\ast(p) | |
\partialp |
.
If one wanted to solve the problem with standard tools such as the implicit function theorem, one would have to assume that the problem is well behaved: U(.) is twice continuously differentiable, concave in s, that the domain over which s is defined is convex, and that it there is a unique maximizer
s\ast(p)
s\ast(p)
Us(s\ast(p),p)=0
Uss(s\ast(p),p)(\partials\ast(p)/(\partialp))+Usp(s\ast(p),p)=0
\partials\ast(p) | |
\partialp |
=\underset{negativeU(.)s}{\underbrace{
-Usp(s\ast(p),p) | |
Uss(s\ast(p),p) |
So,
\partials\ast(p) | |
\partialp |
\overset{sign
If s and p are substitutes,
Usp(s\ast(p),p)<0
and hence
\partials\ast(p) | |
\partialp |
<0
and more potholes causes less speeding. Clearly it is more reasonable to assume that they are substitutes.
The problem with the above approach is that it relies on the differentiability of the objective function and on concavity. We could get at the same answer using Topkis's theorem in the following way. We want to show that
U(s,p)
\left(s,p\right)
\partial2U | |
\partials\partialp |
<0
\partial2U | |
\partials\partialp |
<0,
\partials\ast(p) | |
\partialp |
<0
Hence using the implicit function theorem and Topkis's theorem gives the same result, but the latter does so with fewer assumptions.