Sodium hexachloroiridate(III) is an inorganic compound with the chemical formula Na3IrCl6.
Sodium hexachloroiridate(III) can be produced by the reduction of sodium hexachloroiridate(IV) with Fe2+, oxalate or hydrogen sulfide.[1]
It can also be produced by heating iridium metal with NaCl and Cl2.
Sodium hexachloroiridate(III) will get dehydrated at 110°C, and reversible decomposes at 550°C.[2]
2 Na3IrCl6 ⇌ 2 Ir + 6 NaCl + 3 Cl2
In air, sodium hexachloroiridate(III) will be oxidized at 450°C.[2]
2 Na3IrCl6 + 2 O2 → 2 IrO2 + 6 NaCl + 3 Cl2
It reacts with hydrochloric acid to form hydrogen hexachloroiridate(III).[3]
It also reacts with ammonia water in sealed tube at 145°C to form [Ir(NH<sub>3</sub>)<sub>6</sub>]Cl3.