A=\begin{bmatrix} c&d&e\\ f&g&h\\ \end{bmatrix} | B=\begin{bmatrix} p&q&r\\ s&t&u\\ \end{bmatrix} | |
\begin{array}{c|c|c|c}&X&Y&Z\\ \hline V&c,p&d,q&e,r\\ W&f,s&g,t&h,u\\ \end{array} A payoff matrix converted from A and B where player 1 has two possible actions V and W and player 2 has actions X, Y and Z |
In game theory, a bimatrix game is a simultaneous game for two players in which each player has a finite number of possible actions. The name comes from the fact that the normal form of such a game can be described by two matrices - matrix
A
B
Player 1 is often called the "row player" and player 2 the "column player". If player 1 has
m
n
m
n
i
j
A[i,j]
B[i,j]
The players can also play mixed strategies. A mixed strategy for the row player is a non-negative vector
x
m
y
n
x
y
xTAy
xTBy
Every bimatrix game has a Nash equilibrium in (possibly) mixed strategies. Finding such a Nash equilibrium is a special case of the Linear complementarity problem and can be done in finite time by the Lemke–Howson algorithm.[1]
There is a reduction from the problem of finding a Nash equilibrium in a bimatrix game to the problem of finding a competitive equilibrium in an economy with Leontief utilities.[2]
A zero-sum game is a special case of a bimatrix game in which
A+B=0