Artin's theorem on induced characters explained

In representation theory, a branch of mathematics, Artin's theorem, introduced by E. Artin, states that a character on a finite group is a rational linear combination of characters induced from all cyclic subgroups of the group.

There is a similar but somehow more precise theorem due to Brauer, which says that the theorem remains true if "rational" and "cyclic subgroup" are replaced with "integer" and "elementary subgroup".

Statement

In Linear Representation of Finite Groups Serre states in Chapter 9.2, 17 [1] the theorem in the following, more general way:

Let

G

finite group,

X

family of subgroups.

Then the following are equivalent:

G=cupg\ing-1Hg

\forall\chicharacterofG\existsH\inX,\chiH\inH,d\in\N:d\chi=\sumH\in

G(\chi
Ind
H)

This in turn implies the general statement, by choosing

X

as all cyclic subgroups of

G

.

Proof

Let

G

be a finite groupe and

(\chii)

its irreducible characters. Let us denote, like Serre did in his book,

l{R}(G)

the

Z

-module

oplusi\chiiZ

. Since all of

G

's characters are a linear combination of

(\chii)

with positive integer coefficient, the elements of

l{R}(G)

are the difference of 2 characters of

G

. Moreover, because the product of 2 characters is also a character,

l{R}(G)

is even a ring, a sub-ring of the

C

-algebra of the class function over

G

(of which

(\chii)

forms a basis), which, by tensor product, is isomorphic to

Cl{R}(G)

.Both the restriction

Res

of the representation of

G

to one of its subgroup and its dual operator

Ind

of induction of a representation can be extended to an homomorphisme :

Res:l{R}(G)\tol{R}(H),\sumki\chii\mapsto\sumkiRes

G
H

\chii

Ind:l{R}(H)\tol{R}(G),\sumki\chii\mapsto\sumkiInd

G
H

\chii

With those notations, the theorem can be equivalently re-write as follow :If

X

is a family of subgroup of

G

, the following properties are equivalents :

G

is the reunions of the conjugate of the subgroups of

X

  1. The cokernel of

Ind:oplusH\inl{R}(H)\tol{R}(G)

is finite.

This result from the fact that

l{R}(G)

is of finite type. Before getting to the proof of it, understand that the morphisme

Ind:oplusH\inl{R}(H)\tol{R}(G)

, naturally defined by

(\sum

H)
k
H\inX

\mapsto\sumH\in

H
k
i
G
Res
H

\chii

is well defined because

X

is finite (because

G

is) and its cokernel is

l{R}(G)/Im(Ind)

.

Let’s begin the proof with the implication 2.

\implies

1. Starting with the following lemma :

Let

H

be an element of

X

. Then for every

fH\inl{R}(H)

,
G(f
Ind
H)
is null on

x\inG

if

x

isn’t conjugate to any

h

of

H

. It is enough to prove this assertion for the character

\phiH

of a representation

\theta:H\toGL(W)

of H (as

fH

is a difference of some). Let

\rho:G\toGL(V)

be the induced representation of

G

by

(W,\theta)

. Let now

(ri)

be a system of representative of

G/H

,by definition, V is the direct sum of the transformed
\rho
ri

W

of which

\rhox

is a permutation. Indeed

\rhox\circ\rho

ri
W=\rho
xri
W=\rho
r
ix

W

where

xri=r

ix

t

for some

t\inH

. To evaluate

\chi(x):=Ind(\phi)(x)=TrV(\rhox)

, we can now choose a basis of

V

reunion of basis of the
\rho
ri

W

. In such a basis, the diagonal of the matrix of

\rhox

is null at every

ri

r
ix
, and because

ri=r

ix
would imply

rixr

-1
i

=t\inH

(which is ruled out by hypothesis), it is fully null, we thus have

\chi(x)=TrV(\rhox)=0

which conclude the proof of the lemma.

This particularly insure that, for every element

s

not in

S:=cupg\ing-1Hg

, the elements in the image of

Ind:oplusH\inl{R}(H)\tol{R}(G)

, which are the

\sumH\in

G(f
Ind
H)
evaluate to zero on

s

. The prolonged morphisme

CInd:CoplusH\inl{R}(H)\toCl{R}(G)

has to be surjective. Indeed if not, its cokernel would contain a

VectC(f)

for some

f

in

l{R}(G)

, which in turn means the multiples of

f

are distinct elements of the cokernel of

Ind

contradicting its finitude.Particularly, every element of

Cl{R}(G)

are thus null on the complementary of

S

, insuring

S=G

, thereby concluding the implication.

Let’s now prove 1.

\implies

2.To do so, it is enough to prove that the

C

-linear application

CInd:CoplusH\inl{R}(H)\toCl{R}(G)

is surjective (indeed, in that case,

Cl{R}(G)

would admit a basis

(ei)

composed of element of the image

A

of the

Ind

. It would thus have the same cardinality

n

, than

(\chii)

, insuring that the quotient

l{R}(G)/A

is isomorphic to some
n
Z
i

Hi\cong

nZ/H
\prod
i
which is finite - where the

Hi

are non-trivial ideals of

Z

), which, through duality, is equivalent to prove the injectivity of

CRes:Cl{R}(G)\toCoplusH\inl{R}(H)

Which is obvious : indeed this is equivalent to say that if a class function is null on (at least) one element of each class of conjugation of

G

, it is null (but class function are constant on conjugation class).

This conclude the proof of the theorem.

References

  1. Book: Serre, Jean-Pierre . Linear Representations of Finite Groups . 1977 . Springer New York . 978-1-4684-9458-7 . New York, NY . 853264255.

Further reading