Champ: | Pierre-Hugues Herbert Nicolas Mahut |
Runner: | Julien Benneteau Édouard Roger-Vasselin |
Score: | 6–4, 7–6(7–1), 6–3 |
Draw: | 64 |
Seeds: | 16 |
See main article: article and 2016 Wimbledon Championships.
Jean-Julien Rojer and Horia Tecău were the defending champions, but lost in the first round to Jonathan Marray and Adil Shamasdin.
Pierre-Hugues Herbert and Nicolas Mahut won the title, defeating Julien Benneteau and Édouard Roger-Vasselin in the final, 6–4, 7–6(7–1), 6–3. This was the first all-French men's doubles final at Wimbledon.
Due to inclement weather, all first and second round matches were best-of-three sets instead of best-of-five.[1]
See main article: article and 2016 Wimbledon Championships – Men's doubles qualifying.