1958 United States Senate election in Florida explained

Election Name:1958 United States Senate election in Florida
Country:Florida
Type:presidential
Ongoing:no
Previous Election:1952 United States Senate election in Florida
Previous Year:1952
Next Election:1964 United States Senate election in Florida
Next Year:1964
Election Date:November 4, 1958
Image1:Spessard Holland.JPG
Nominee1:Spessard Holland
Party1:Democratic Party (United States)
Popular Vote1:386,113
Percentage1:71.23%
Nominee2:Leland Hyzer
Party2:Republican Party (United States)
Popular Vote2:155,956
Percentage2:28.77%
Map Size:280px
U.S. Senator
Before Election:Spessard Holland
Before Party:Democratic Party (US)
After Election:Spessard Holland
After Party:Democratic Party (US)
Flag Year:1900

The 1958 United States Senate election in Florida was held on November 4, 1958.

After fending off a primary challenge from former senator Claude Pepper, the incumbent senator Spessard Holland was easily re-elected to a third term in office.

Democratic primary

Candidates

Campaign

The incumbent senator Holland, a firm conservative, was challenged by former senator Claude Pepper, who had been unseated in 1950. Holland had played a role in recruiting George A. Smathers to run against the liberal Pepper in that election. The two served as colleagues in the Senate from 1947 to 1951.[1] 26.4% of the voting age population participated in the Democratic primary.

Results

Republican primary

Candidates

Results

Hyzer was unopposed for the Republican nomination.

General election

Results

See also

Works cited

Notes and References

  1. News: Egerton . John . November 29, 1981 . COURTLY CHAMPION OF AMERICA'S ELDERLY . The New York Times . August 15, 2019.