1946 Minnesota Attorney General election explained

Election Name:1946 Minnesota Attorney General election
Country:Minnesota
Type:Presidential
Ongoing:no
Previous Election:1944 Minnesota Attorney General election
Previous Year:1944
Next Election:1948 Minnesota Attorney General election
Next Year:1948
Election Date:5 November 1946
Nominee1:Joseph A. A. Burnquist
Party1:Republican Party (United States)
Popular Vote1:526,331
Percentage1:61.77%
Nominee2:Walter C. Boland
Party2:Minnesota Democratic–Farmer–Labor Party
Popular Vote2:325,764
Percentage2:38.23%
Attorney General
Before Election:Joseph A. A. Burnquist
Before Party:Republican Party (United States)
After Election:Joseph A. A. Burnquist
After Party:Republican Party (United States)

The 1946 Minnesota Attorney General election was held on 5 November 1946 in order to elect the attorney general of Minnesota. Republican nominee and incumbent attorney general Joseph A. A. Burnquist defeated Democratic–Farmer–Labor nominee Walter C. Boland.[1]

General election

On election day, 5 November 1946, Republican nominee Joseph A. A. Burnquist won re-election by a margin of 200,567 votes against his opponent Democratic–Farmer–Labor nominee Walter C. Boland, thereby retaining Republican control over the office of attorney general. Burnquist was sworn in for his fifth term on 3 January 1947.[2]

Results

Notes and References

  1. Web site: Attorney General, 1946 Election . electionarchives.lib.umn.edu . 8 October 2024.
  2. Web site: MN Attorney General . ourcampaigns.com . 7 March 2019 . 8 October 2024.