1850 Ohio gubernatorial election explained

Election Name:1850 Ohio gubernatorial election
Country:Ohio
Type:Presidential
Ongoing:no
Previous Election:1848 Ohio gubernatorial election
Previous Year:1848
Next Election:1851 Ohio gubernatorial election
Next Year:1851
Election Date:8 October 1850
Nominee1:Reuben Wood
Party1:Democratic Party (United States)
Popular Vote1:133,093
Percentage1:49.67%
Nominee2:William Johnston
Party2:Whig Party (United States)
Popular Vote2:121,105
Percentage2:45.20%
Nominee3:Edward Smith
Party3:Free Soil Party
Popular Vote3:13,747
Percentage3:5.13%
Governor
Before Election:Seabury Ford
Before Party:Whig Party (United States)
After Election:Reuben Wood
After Party:Democratic Party (United States)

The 1850 Ohio gubernatorial election was held on 8 October 1850, in order to elect the Governor of Ohio. Democratic nominee and former Justice of the Ohio Supreme Court Reuben Wood defeated Whig nominee and former member of the Ohio House of Representatives William Johnston and Free Soil nominee Edward Smith.[1]

General election

On election day, 8 October 1850, Democratic nominee Reuben Wood won the election by a margin of 11,988 votes against his foremost opponent Whig nominee William Johnston, thereby gaining Democratic control over the office of Governor. Wood was sworn in as the 21st Governor of Ohio on 12 December 1850.[2]

Results

Notes and References

  1. Web site: Reuben Wood . 10 May 2024 . National Governors Association.
  2. Web site: OH Governor . ourcampaigns.com . 6 October 2012 . 10 May 2024.