See main article: 1836 United States presidential election.
| Election Name: | 1836 United States presidential election in Illinois |
| Country: | Illinois |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1832 United States presidential election in Illinois |
| Previous Year: | 1832 |
| Next Election: | 1840 United States presidential election in Illinois |
| Next Year: | 1840 |
| Election Date: | November 3 – December 7, 1836 |
| Image1: | Martin Van Buren circa 1837 crop.jpg |
| Nominee1: | Martin Van Buren |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Richard Johnson |
| Electoral Vote1: | 5 |
| Popular Vote1: | 18,369 |
| Percentage1: | 54.69% |
| Nominee2: | William Henry Harrison |
| Party2: | Whig Party (United States) |
| Home State2: | Ohio |
| Running Mate2: | Francis Granger |
| Electoral Vote2: | 0 |
| Popular Vote2: | 15,220 |
| Percentage2: | 45.31% |
| Map Size: | 180px |
The 1836 United States presidential election in Illinois took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 9.38%. This is the last time Ogle County voted Democratic.
| 1836 United States presidential election in Illinois[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 18,369 | 54.69% | 5 | |
| Whig | William Henry Harrison | 15,220 | 45.31% | 0 | |
| Totals | 33,589 | 100.0% | 5 | ||