| Election Name: | 1813 New Jersey gubernatorial election |
| Country: | New Jersey |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1812 New Jersey gubernatorial election |
| Previous Year: | 1812 |
| Next Election: | 1814 New Jersey gubernatorial election |
| Next Year: | 1814 |
| Election Date: | 29 October 1813 |
| Nominee1: | William Sanford Pennington |
| Party1: | Democratic-Republican Party |
| Popular Vote1: | 30 |
| Percentage1: | 60.00% |
| Nominee2: | Aaron Ogden |
| Party2: | Federalist Party |
| Popular Vote2: | 20 |
| Percentage2: | 40.00% |
| Governor | |
| Before Election: | Aaron Ogden |
| Before Party: | Federalist Party |
| After Election: | William Sanford Pennington |
| After Party: | Democratic-Republican Party |
The 1813 New Jersey gubernatorial election was held on 29 October 1813 in order to elect the governor of New Jersey. Democratic-Republican nominee and former United States Attorney for the District of New Jersey William Sanford Pennington was elected by the New Jersey General Assembly against incumbent Federalist governor Aaron Ogden.[1]
On election day, 29 October 1813, Democratic-Republican nominee William Sanford Pennington was elected by the New Jersey General Assembly by a margin of 10 votes against his opponent incumbent Federalist governor Aaron Ogden, thereby gaining Democratic-Republican control over the office of governor. Pennington was sworn in as the 6th governor of New Jersey that same day.[2]