See main article: 1796 United States presidential election.
Election Name: | 1796 United States presidential election in Kentucky |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1792 United States presidential election in Kentucky |
Previous Year: | 1792 |
Next Election: | 1800 United States presidential election in Kentucky |
Next Year: | 1800 |
Election Date: | 4 November - 7 December 1796 |
Image1: | Thomas Jefferson by Rembrandt Peale, 1800.jpg |
Nominee1: | Thomas Jefferson |
Party1: | Democratic-Republican Party (United States) |
Home State1: | Virginia |
Running Mate1: | Aaron Burr |
Electoral Vote1: | 4 |
Percentage1: | 100.00% |
Nominee2: | John Adams |
Party2: | Federalist Party (United States) |
Home State2: | Massachusetts |
Running Mate2: | Thomas Pinckney |
Electoral Vote2: | 0 |
Percentage2: | 0.00% |
The 1796 United States presidential election in Kentucky took place between 4 November and 7 December 1796, as part of the 1796 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky cast four electoral votes for the Democratic-Republican candidate Thomas Jefferson over the Federalist candidate and incumbent Vice President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors.[1]
1796 United States presidential election in Kentucky[2] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Thomas Jefferson | — | 100.00% | 4 | |
Federalist | John Adams | — | 0.00% | 0 | |
Totals | — | 100.00% | 4 | ||