See main article: 1796 United States presidential election.
| Election Name: | 1796 United States presidential election in Georgia |
| Country: | Georgia (U.S. state) |
| Type: | presidential |
| Previous Election: | 1792 United States presidential election in Georgia |
| Previous Year: | 1792 |
| Next Election: | 1800 United States presidential election in Georgia |
| Next Year: | 1800 |
| Election Date: | 4 November |
| Image1: | Thomas Jefferson by Rembrandt Peale, 1800.jpg |
| Nominee1: | Thomas Jefferson |
| Party1: | Democratic-Republican Party (United States) |
| Home State1: | Virginia |
| Running Mate1: | Aaron Burr |
| Electoral Vote1: | 4 |
| Popular Vote1: | 6,200 |
| Percentage1: | 70.10% |
| Nominee2: | John Adams |
| Party2: | Federalist Party (United States) |
| Home State2: | Massachusetts |
| Running Mate2: | Thomas Pinckney |
| Electoral Vote2: | 0 |
| Popular Vote2: | 2,644 |
| Percentage2: | 29.9% |
The 1796 United States presidential election in Georgia took place on 4 November 1796, as part of the 1796 United States presidential election. The voters chose four representatives, or electors, through plurality block voting to the Electoral College. These electors then voted for President and vice president.[1]
Out of 51 elector candidates, four Democratic-Republican electors were elected who then voted for Thomas Jefferson over the Federalist candidate and incumbent vice President John Adams. The electoral votes for vice president were however not cast for Jefferson's running mate Aaron Burr, but for George Clinton from New York.[2]
| 1796 United States presidential election in Georgia[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson | 6,200 | 70.10% | 4 | |
| Federalist | John Adams | 2,644 | 29.9% | 0 | |
| Totals | 8,844 | 100.00% | 4 | ||